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phantranbaonguyen
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Tạ Thu Hương
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Trúc Giang
4 tháng 8 2020 lúc 21:28

a/ \(3x^2-5x-2\)

\(=3x^2-3x-2x-2\)

\(=3x\left(x-1\right)+2\left(x-1\right)\)

\(=\left(x-1\right)\left(3x+2\right)\)

b/ \(2x^2+x-6\)

\(=2x^2+4x-3x-6\)

\(=2x\left(x+2\right)+3\left(x+2\right)\)

\(=\left(x+2\right)\left(2x+3\right)\)

c/ \(7x^2+50x+7\)

\(=7x^2+49x+x+7\)

\(=7x\left(x+7\right)+\left(x+7\right)\)

\(=\left(x+7\right)\left(7x+1\right)\)

d/ \(12x^2+7x-12\)

\(=12x^2-9x+16x-12\)

\(=3x\left(4x-3\right)+4\left(4x-3\right)\)

\(=\left(4x-3\right)\left(3x+4\right)\)

e/ \(15x^2+7x-2\)

\(=15x^2+10x-3x-2\)

\(=5x\left(3x+2\right)-\left(3x+2\right)\)

\(=\left(3x+2\right)\left(5x-1\right)\)

f/ \(a^2-5a-14\)

\(=a^2+2a-7a-14\)

\(=a\left(a+2\right)-7\left(a+2\right)\)

\(=\left(a+2\right)\left(a-7\right)\)

g/ \(2m^2+10m+8\)

\(=2m^2+2m+8m+8\)

\(=2m\left(m+1\right)+8\left(m+1\right)\)

\(=\left(m+1\right)\left(2m+8\right)\)

h/ \(4p^2-36p+56\)

\(=4p^2-28p-8p+56\)

\(=4p\left(p-7\right)-8\left(p-7\right)\)

\(=\left(p-7\right)\left(4p-8\right)\)

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Oh Sehun
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💋Amanda💋
19 tháng 8 2019 lúc 20:34
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kinokinalisa
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Nguyễn Phương Uyên
1 tháng 7 2019 lúc 11:51

2x^2 + x - 6

= 2x^2 + 4x - 3x - 6

= 2x(x + 2) - 3(x + 2)

= (2x - 3)(x + 2)

7x^2 + 50x + 7 

= 7x^2 + x + 49x + 7

= 7x(x + 7) + x + 7

= (7x + 1)(x + 7)

12x^2 + 7x - 12

15x^2 +  7x - 2

= 15x^2 - 3x + 10x - 2

= 3x(5x - 1) + 2(5x - 1) 

= (3x + 2)(5x - 1)

a^2 - 5a - 14

= a^2 + 2a - 7a - 14

= a(a + 2) - 7(a + 2)

= (a - 7)(a + 2)

2x^2 + 5x + 2

= 2x^2 + x + 4x + 2

= 2x(x + 2) + x + 2

= (2x + 1)(x + 2)

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Nguyễn Thị Bích Ngọc
1 tháng 7 2019 lúc 11:51

\(2x^2+x-6=2x^2+4x-3x-6\)

\(=2x\left(x+2\right)-3\left(x+2\right)\)

\(=\left(x+2\right)\left(2x-3\right)\)

\(7x^2+50x+7\)

\(=7x^2+x+49x+7\)

\(=x\left(7x+1\right)+7\left(7x+1\right)\)

\(=\left(7x+1\right)\left(x+7\right)\)

\(12x^2+7x-12\)

\(=12x^2+16x-9x-12\)

\(=4x\left(3x+4\right)-3\left(3x+4\right)\)

\(=\left(3x+4\right)\left(4x-3\right)\)

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Nguyễn Thị Bích Ngọc
1 tháng 7 2019 lúc 11:54

\(4p^2-36p+56\)

\(=4p^2+8p+28p+56\)

\(=4p\left(p+2\right)+28\left(p+2\right)\)

\(=\left(p+2\right)\left(4p+28\right)\)

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Oh Sehun
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Edogawa Conan
19 tháng 8 2019 lúc 20:37

Bài 1: a) x2 - 5x + 6 = x2 - 2x - 3x + 6 = x(x - 2) - 3(x - 2) = (x - 3)(x - 2)

b) 3x2 + 9x - 30 = 3x2 + 15x - 6x - 30 = 3x(x + 5) - 6(x + 5) = (3x - 6)(x + 5) = 2(x - 2)(x + 5)

c) x2 - 3x + 2 = x2 - 2x - x + 2  = x(x - 2) - (x - 2) = (x - 1)(x - 2)

d) x2 - 9x + 18 = x2 - 3x - 6x + 18 = x(x - 3) - 6(x - 3) = (x - 6)(x - 3)

e) x2 - 6x + 8 = x2 - 2x - 4x + 8 = x(x - 2) - 4(x - 2) = (x - 4)(x - 2)

f) x2 - 5x - 14 = x2 - 7x + 2x - 14 = x(x - 7) + 2(x - 7) = (x + 2)(x - 7)

g) x2 + 6x + 5 = x2 + 5x + x + 5 = x(x + 5) + (x + 5) = (x + 1)(x + 5)

h) x2 - 7x + 12 = x2 - 3x - 4x + 12 = x(x - 3) -  4(x - 3) = (x - 4)(x - 3)

i) x2 - 7x + 10 = x2 - 2x - 5x + 10 = x(x - 2) - 5(x - 2) = (x - 5)(x - 2)

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zZz Cool Kid_new zZz
19 tháng 8 2019 lúc 20:40

Oh Sehun:Ít một thôi bạn ơi!Làm xong đống này chắc đến tuổi già mất:(

a

\(x^2-5x+6\)

\(=\left(x^2-3x\right)-\left(2x-6\right)\)

\(=\left(x-3\right)\left(x-2\right)\)

b

\(3x^2+9x-30\)

\(=x^2+3x-10\)

\(=\left(x^2-2x\right)+\left(5x-10\right)\)

\(=\left(x-2\right)\left(x+5\right)\)

c

\(x^2-3x+2\)

\(=\left(x^2-x\right)-\left(2x-2\right)\)

\(=\left(x-1\right)\left(x-2\right)\)

d

\(x^2-9x+18\)

\(=\left(x^2-3x\right)-\left(6x-18\right)\)

\(=\left(x-3\right)\left(x-6\right)\)

e

\(x^2-6x+8\)

\(=\left(x^2-2x\right)-\left(4x-8\right)\)

\(=\left(x-2\right)\left(x-4\right)\)

f

\(x^2-5x-14\)

\(=\left(x^2+2x\right)-\left(7x+14\right)\)

\(=\left(x+2\right)\left(x-7\right)\)

g

\(x^2+6x+5\)

\(=\left(x^2+x\right)+\left(5x+5\right)\)

\(=\left(x+1\right)\left(x+5\right)\)

h

\(x^2-7x+12\)

\(=\left(x^2-3x\right)-\left(4x-12\right)\)

\(=\left(x-3\right)\left(x-4\right)\)

i

\(x^2-7x+10\)

\(=\left(x^2-2x\right)-\left(5x-10\right)\)

\(=\left(x-2\right)\left(x-5\right)\)

P/S:Cho e xin phép tách câu ạ.

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Edogawa Conan
19 tháng 8 2019 lúc 20:46

Bài 2: a) xlđ

b) 2x2 +  x  - 6 = 2x2 + 4x - 3x - 6 = 2x(x + 2) - 3(x + 2) = (2x - 3)(x + 2)

c) 7x2 + 50x + 7 = 7x2 + x + 49x + 7 = x(7x + 1) + 7(7x + 1) = (x + 7)(7x + 1)

d) 12x2 + 7x - 12 = 12x2 + 16x - 9x - 12 = 4x(3x + 4) - 3(3x + 4) = (4x - 3)(3x + 4)

e) 15x2 + 7x - 2 = 15x2 + 10x - 3x - 2 =5x(3x + 2) - (3x + 2) = (5x - 1)(3x + 2)

f) a2 - 5a - 14 = a2 - 7a + 2a - 14 = a(a - 7) + 2(a - 7) = (a + 2)(a - 7_

g) 2m2 + 10m + 8 = 2m2 + 2m + 8m + 8 = 2m(m + 1) + 8(m + 1) = (2m + 8)(m + 1) = 2(m + 4)(m + 1)

h) 4p2 - 36p + 56 = 4(p2 - 9p + 14) = 4(p2 - 2p - 7p + 14) = 4[p(p - 2) - 7(p - 2)] = 4(p - 7)(p - 2)

i) 2x2 + 5x + 2 = 2x2 + x + 4x + 2 = x(2x + 1) + 2(2x + 1) = (x + 2)(2x + 1)

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Nguyễn Võ Nhiệt My
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Huỳnh Thoại
22 tháng 8 2016 lúc 15:09

a) \(x^2\)\(-5x+6\)

=\(x^2\)\(-3x-2x+6\)

=\(x\left(x-3\right)-2\left(x-3\right)\)

=\(\left(x-2\right)\left(x-3\right)\)

b) \(3x^2\)\(+9x-30\)

=\(3x^2\)\(-6x+15x-30\)

=\(3x\left(x-2\right)+15\left(x-2\right)\)

=\(\left(x-2\right)\left(3x+15\right)\)

c)\(x^2\)\(-3x+2\)

=\(x^2\)\(-2x-x+2\)

=\(x\left(x-2\right)-\left(x-2\right)\)

=\(\left(x-2\right)\left(x-1\right)\)

d) \(12x^2\)\(+7x-12\)

=\(12x^2\)\(-9x+16x-12\)

=\(3x\left(4x-3\right)+4\left(4x-3\right)\)

=\(\left(3x+4\right)\left(4x-3\right)\)

e) \(15x^2\)\(+7x-2\)

=\(15x^2\)\(-3x+10x-2\)

=\(3x\left(5x-1\right)+2\left(5x-1\right)\)

=\(\left(3x+2\right)\left(5x-1\right)\)

f) \(a^2\)\(-5a-14\)

=\(a^2\)\(-7a+2a-14\)

=\(a\left(a-7\right)+2\left(a-7\right)\)

=\(\left(a+2\right)\left(a-7\right)\)

g) \(x^2\)\(-\left(a+b\right)x+ab\)

=\(x^2\)\(-ax-bx+ab\)

=\(x\left(x-a\right)-b\left(x-a\right)\)

=\(\left(x-a\right)\left(x-b\right)\)

 

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Hắc Hàn Nan Thiên
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bella nguyen
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Hoàng Anh Shiho
29 tháng 9 2016 lúc 21:29

a, x^2 + 5x +4

= x^2 + 1x + 4x + 4

= (x^2 + 1x) + (4x + 4)

= x ( x + 1 ) + 4 ( x + 1 )

= (x + 1) (x + 4)

b, x^2 - 6x + 5

= x^2 - 1x - 5x + 5

= (x^2 - 1x) - (5x - 5)

= x (x - 1) - 5 (x - 1)

= (x - 1) (x - 5)

c, x^2 + 7x + 12

= x^2 + 3x + 4x + 12 

= (x^2 + 3x) + (4x + 12)

= x (x + 3) + 4 (x + 3)

= (x + 3) (x + 4)

d, 2x^2 - 5x + 3

= 2^x2 - 2x - 3x + 3

= 2x (x - 1) - 3 (x - 1)

= (x-1) (2x - 3)

e, 7x  - 3x^2 - 4

= 3x + 4x - 3x^2 - 4

= (3x - 3x^2) + (4x - 4)

= 3x (1 - x) + 4 (x - 1)

= 3x (1-x) - 4 (1 - x)

= (1 - x) (3x - 4)

f, x^2 - 10x + 16

= x^2 - 2x - 8x + 16

= (x^2 - 2x) - (8x - 16)

= x (x - 2) - 8 (x - 2)

= (x - 2) (x - 8)

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Vũ Đức Toàn
29 tháng 9 2016 lúc 21:30

a, (x+1)(x+4)

b,(x-5)(x-1)

c,(x+3)(x+4)

d,(2x-3)(x-1)

e,(-3x+4)(x-1)

f, (x-8)(x-2)

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Sương Nguyễn
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Nguyễn Lê Phước Thịnh
29 tháng 8 2023 lúc 12:59

a: x^3-7x-6

=x^3-x-6x-6

=x(x-1)(x+1)-6(x+1)

=(x+1)(x^2-x-6)

=(x-3)(x+2)(x+1)

b: =2x^3+x^2-2x^2-x+6x+3

=x^2(2x+1)-x(2x+1)+3(2x+1)

=(2x+1)(x^2-x+3)

c: =2x^3-3x^2-2x^2+3x+2x-3

=x^2(2x-3)-x(2x-3)+(2x-3)

=(2x-3)(x^2-x+1)

d: =2x^3+x^2+2x^2+x+2x+1

=(2x+1)(x^2+x+1)

e: =3x^3+x^2-3x^2-x+6x+2

=(3x+1)(x^2-x+2)

f: =27x^3-9x^2-18x^2+6x+12x-4

=(3x-1)(9x^2-6x+4)

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Thanh Phong (9A5)
29 tháng 8 2023 lúc 13:13

a) \(x^3-7x-6\)

\(=x^3-x-6x-6\)

\(=\left(x^3-x\right)-\left(6x+6\right)\)

\(=x\left(x^2-1\right)-6\left(x+1\right)\)

\(=x\left(x+1\right)\left(x-1\right)-6\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2-x-6\right)\)

b) \(2x^3-x^2+5x+3\)

\(=2x^3+x^2-2x^2-x+6x+3\)

\(=\left(2x^3+x^2\right)-\left(2x^2+x\right)+\left(6x+3\right)\)

\(=x^2\left(2x+1\right)-x\left(2x+1\right)+3\left(2x+1\right)\)

\(=\left(x^2-x+3\right)\left(2x+1\right)\)

c) \(2x^3-5x^2+5x+1\)

\(=2x^3-3x^2-2x^2+3x+2x-3\)

\(=\left(2x^3-3x^2\right)-\left(2x^2-3x\right)+\left(2x-3\right)\)

\(=x^2\left(2x-3\right)-x\left(2x-3\right)+\left(2x-3\right)\)

\(=\left(x^2-x+1\right)\left(2x-3\right)\)

d) \(2x^3+3x^2+3x+1\)

\(=2x^3+x^2+2x^2+x+2x+1\)

\(=\left(2x^3+x^2\right)+\left(2x^2+x\right)+\left(2x+1\right)\)

\(=x^2\left(2x+1\right)+x\left(2x+1\right)+\left(2x+1\right)\)

\(=\left(2x+1\right)\left(x^2+x+1\right)\)

e) \(3x^3-2x^2+5x+2\)

\(=3x^3+x^2-3x^2-x+6x+2\)

\(=\left(3x^3+x^2\right)-\left(3x^2+x\right)+\left(6x+2\right)\)

\(=x^2\left(3x+1\right)-x\left(3x+1\right)+2\left(3x+1\right)\)

\(=\left(3x-1\right)\left(x^2-x+2\right)\)

f) \(27x^3-27x^2+18x-4\)

\(=27x^3-9x^2-18x^2+6x+12x-4\)

\(=\left(27x^3-9x^2\right)-\left(18x^2-6x\right)+\left(12x-4\right)\)

\(=9x^2\left(3x-1\right)-6x\left(3x-1\right)+4\left(3x-1\right)\)

\(=\left(3x-1\right)\left(9x^2-6x+4\right)\)

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